Two mili containers contain 398L and 436L of milk. The milk is to be transferred to another container with the help of a drum . While transferring to another container 7L and 11L of milk is left in both the containers respectively. What will be the maximum capacity of the drum?
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in easy words,the question is asking the maximum no which divides 398 and 436 leaving remainders 7 amd 11 respectively
so find the hcf of (391,425)=17
so capacity of drum is 17 litres since that will leave 7 and 11 litres respectively
so find the hcf of (391,425)=17
so capacity of drum is 17 litres since that will leave 7 and 11 litres respectively
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