two milk containers contains 398 L and 436 L of milk.The milk is to be transferred to another container with the help of a drum.While transferring to another container 7 L and 11 L of milk is left in both the containers respectively.What will be the maximum capacity of the drum.
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If 7L is left over in the first container then amt of milk poured in the drum from that container is(398-7)=391L. From the next one it is(436-11)=425L. Therefore, total capacity of the drum is(391+425)=816L.
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Yes, You are right Urna the capacity of the drum is 816 L.
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Hope it helped you.
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