Question

Two moles of an ideal monoatomic gas is heated at constant pressure from 270 c to 1270 c.Calculate the work done.

Answer 1

HELLO THERE!

Given that pressure is constant in the process,

So, the process is Isobaric.

Now, from the Ideal Gas equation,

PV = nRT

or, PdV + VdP = nR dT (Differentiating both sides)

As, Pressure is constant, dP = 0

So, we now have,

PdV = nR (T₂ - T₁) [Convert the temperatures to Kelvin]

PdV = Work done, so:

Work = 2 × 8.314 × (1543 - 543)

= 2 × 8.314 × 1000

= 16,628 Joule

Correct me if I'm wrong :)

Thanks!