Two moles of ideal diatomic gas ( Cv = 5/2 R ) at 300 k and 5 atm expanded irreversibly and adiabatically to a final pressure of 2 atm against a contant pressure of 1 atm.
calculate q , w, delta h and delta U
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The value of q, w, ΔH and ΔU are:
- 2 moles of ideal diatomic gas at 300 K and 5 atm is expanded irreversibly and adiabatically to a final pressure of 2 atm against a constant pressure of 1 atm.
- Given, = 1 atm
P₁ = 5 atm T₁ = 300 K
P₂ = 2 atm T₂ = T = ?
n = 2
= 2.5 R
- For adiabatic process, q=0.
- For an adiabatic process, W = n dT= −PΔV
⇒ n ( T₂ - T₁ ) = - P ( V₂ - V₁ )
⇒ n ( T₂ - T₁ ) = - P n R ( (T₂/P₂) - (T₁/P₁))
Putting the values and solving it, we get : T₂ = T = 270 K
- W = n dT = -1247.1 J
- ΔU = W = -1247.1 J
- ΔH = ΔU + n R ΔT = − 1745.94 J
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