Question

Two moles of N2 and two moles of H2 are taken in a closed vessel of 5 litres capacity and suitable conditions are provided for the reaction . When the equilibrium is reached it is found that a half mole of N2is used up. What is the equilibrium concentration of NH3?

Answer 1

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Answer 2

Hence the number of moles of NH3 are 0.2 moles

Explanation:

N2 (g)  + 3H  2  (g)  ⇋ 2NH3 (g)

​Given that when the equilibrium is reached, it is found that a half mole of N2   is used up, i.e.

Amount of N2  used =0.5 moles

Amount of NH3 produced by 1 mole of N  2   = 2 moles

⇒ Amount of NH  3  produced by 0.5 mole of N2  = 1 mole

Volume of vessel = 5 L

Equilibrium concentration of NH 3  = Volume  /  No. of moles  =  5  / 1

Equilibrium concentration of NH 3   = 0.2 moles

Hence the number of moles of NH3 are 0.2 moles