Question

Two moles of organic compound a on treatment with a strong base gives two compounds b and c. Compound b on dehydrogenation with cu gives a while acidification of c yields carboxylic acid d with molecular formula of ch2o2. Identify the compounds a, b, c and d. Write all chemical reactions involved.

Answer 1

A is formaldehyde, B is methanol, C is formate and d is formic acid.

Explanation:

• The compound D has the formula of CH2O2.

• As there's no step of decarboxylation, so the main chain also contains the carbon number 1.

• The 1st reaction where the treatment with a strong base yields two compounds is the Cannizaro reaction.

• The reactant A is then formaldehyde.

• It reacts with concentrated sodium hydroxide to form methanol and formate ion.

• The reaction is a disproportionation reaction.

1. This reaction yields product B which is methanol which when treated with Cu +H2 gives back the formaldehyde.

• The product B is the salt of formic acid.

• It when treated with a mineral acid, gives back the formic acid with emperical formula CH2O2.

For more information about Cannizaro reaction,

https://brainly.in/question/14839459

The cannizzaro's reaction is given by​ - Brainly.in

https://brainly.in/question/13569795

What is crossed cannizzaro reaction? Explain with their mechanism.

Answer 2

Explanation:

Two moles of organic compound a on treatment with a strong base gives two compounds b and c

. Compound b on dehydrogenation with cu gives a while acidification of c yields carboxylic acid✔️

d with molecular formula of ch2o2. Identify the compounds a, b, c and d. Write all chemical reactions involved.