Two motor car starting off with a time gap of 2 minute, travel in the same direction with the same direction with the same acceleration. Time taken by the second car since its departure to complete (1/9)™of the distance covered by the first car is
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16
Answer:
Explanation:
Let t be time in seconds when the second car has travelled (1/9)th of distance travelled by first car as given in question.
There is a gap of 2 min or 120 s between the starting time of both the cars.
Distance travelled by first car, S1 = (1/2)×a×(120+t)2 .................(1)
Distance travelled by Second car, S2 = (1/2)×a×t2 ..................(2)
if S2 = (1/9)S1, then (1/18)×a×(120+t)2 = (1/2)×a×t2 ...........(3)
solving for t in eqn.(3), we get t = 60 s
Answered by
1
Answer:
60 seconds=1 minute
Explanation:
hope it helps you
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