Two motor mechanics , Raju and Siraj , working together can overhaul a scooter in 6hrs. Raju alone can do the job in 15 hrs. In how many hours can Siraj alone do it?
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Let Raju takes 'x' hours and Siraj 'y' hours to complete the work alone.
As given in question, x=15hrs that is Raju takes15 hrs to complete 1 work or we can say
1/15 work is done by Raju in 1 hr. (6 hr work=6/15)
Similarly, 1/y work is done by Siraj in 1 hr.( 6 hr work=6/y)
according to question
6/15+1/y=1
1/y=9/15=3/5
y=5/3 days
As given in question, x=15hrs that is Raju takes15 hrs to complete 1 work or we can say
1/15 work is done by Raju in 1 hr. (6 hr work=6/15)
Similarly, 1/y work is done by Siraj in 1 hr.( 6 hr work=6/y)
according to question
6/15+1/y=1
1/y=9/15=3/5
y=5/3 days
sharankaler:
plz tell me how you solve this sum?
6/15+1/y=1
6/15+1/y=1
1/y=1-6/15 =1-2/5 now take lcm then (5-2)/5=3/5 next cross multiply and please tell me how to delete comments here. I am new here hence still figuring this out..
1/y=1-6/15 =1-2/5 now take lcm then (5-2)/5=3/5 next cross multiply and please tell me how to delete comments here. I am new here hence still figuring this out..
I am new here
I don't know
how to delete
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