Question

Two mumbers are in the ratio of 1: 2. If sum
of their squares is 320, then find the sum of
numbers.

Answer 1

Let the two numbers be x and 2x

 given, sum  of their squares is 320

So $x^{2} + (2x)^2 = 320$

    $x^2+4x^2=5x^2=320$

         $x^2= 64 \\x = +8 or -8$

Considering x =8

then sum of no.s = x+ 2x = 3x = 3(8) = 24

considering x = -8

sum of no.s  = (-8) + 2(-8) = -24

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Answer 2

Answer:

24

Step-by-step explanation:

Let the numbers be x and 2x

Sum of squares is 320 :  $x^{2} + 4x^{2} =320$

                                       $[5x]^{2} = 320$

                                         $x^{2} =\frac{320}{5}$

                                         $x^{2} = 64$

                                         $x =8$

So the numbers are 8 and 16.

There sum equals 24.