two natural number are selected from first 60 natural number and are multipled. what is the probability that their product is divisible by 4
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Answer:
Correct option is
C
10
1
Let the two non-negative integers selected be a and b.
Then a=10α+a
1
and b=10β+b
1
,
where α,β≥0 and 0<a
1
,b
1
≤9
Thus, number of possible cases for (a
1
,b
1
) is 10×10=100
Out of these 100, (0,0),(1,9),(2,8),(3,7),(4,6),(5,5),(6,4),(7,3),(8,2) and (9,1) are favourable.
Hence, the probability of the required event is
100
10
=
10
1
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