Math, asked by komalkaur350, 9 months ago

two natural number where difference is 66 and last is 360 on then the two numbers are (i) 120 and 54 , (ii) 90 and 24 , (iii) 180 and 114 , (iv) 130 and 64.


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Answers

Answered by shadowsabers03
7

Question:-

Two natural numbers are such that their difference is 66 and LCM is 360. Then the two numbers are,

(i) 120 and 54

(ii) 90 and 24

(iii) 180 and 114

(iv) 130 and 64

Answer:-

(ii) 90 and 24

Solution:-

Well, each pair of natural numbers in the options differ by 66. So let's check which pair of numbers have LCM 360.

(i) LCM of 120 and 54

\displaystyle\longrightarrow\sf{6\times20\times9=1080\neq360}

(ii) LCM of 90 and 24

\displaystyle\longrightarrow\sf{6\times15\times4=360}

(iii) LCM of 180 and 114

\displaystyle\longrightarrow\sf{6\times30\times19=3420\neq360}

(iv) LCM of 130 and 64

\displaystyle\longrightarrow\sf{2\times65\times32=4160\neq360}

So (ii) 90, 24 is the answer.

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