Two number are in the ratio 2:3 if 4 is subtract each they are in the ratio 3:5 find the numbers
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Answered by
3
HEY DEAR ... ✌️
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Here's , Ur Answer :-
two numbers are common multiple are x ---(1)
2x:3x
subtract the this ratio
4-2x:4-3x------(1)
subtracted ratio are 3:5
3x:5x----------------from1 ---2epu
(1)and(2)epution are epul
4-2x:4-3x=3x:5x
x=8
1th number 2x=2*8=16
2th number 3x=3*8=24
________________________
HOPE , IT HELPS ... ✌️
_______________________
_______________________
Here's , Ur Answer :-
two numbers are common multiple are x ---(1)
2x:3x
subtract the this ratio
4-2x:4-3x------(1)
subtracted ratio are 3:5
3x:5x----------------from1 ---2epu
(1)and(2)epution are epul
4-2x:4-3x=3x:5x
x=8
1th number 2x=2*8=16
2th number 3x=3*8=24
________________________
HOPE , IT HELPS ... ✌️
Answered by
5
Given ratio of two nos.=2:3
Let the common ratio be x.
Then the nos. are 2x and 3x.
Now given,
If 4 is subtracted from each of the numbers then they are in the ratio 3:5.
Then on subtracting 4 from each no.,the nos. become (2x-4) and (3x-4).
Present ratio=3:5
ATP,
(2x-4):(3x-4)=3:5
=)(2x-4)/(3x-4)=3/5
=)5(2x-4)=3(3x-4)
=)10x-20=9x-12
=)10x-9x=20-12
=)x=8.
Then the nos. are
2x=2×8=16
3x=3×8=24.
Hope it helped u.
Please if u please me please please please please please please please please please please please please please please please please please please please mark it as BRAINLIEST.
Let the common ratio be x.
Then the nos. are 2x and 3x.
Now given,
If 4 is subtracted from each of the numbers then they are in the ratio 3:5.
Then on subtracting 4 from each no.,the nos. become (2x-4) and (3x-4).
Present ratio=3:5
ATP,
(2x-4):(3x-4)=3:5
=)(2x-4)/(3x-4)=3/5
=)5(2x-4)=3(3x-4)
=)10x-20=9x-12
=)10x-9x=20-12
=)x=8.
Then the nos. are
2x=2×8=16
3x=3×8=24.
Hope it helped u.
Please if u please me please please please please please please please please please please please please please please please please please please please mark it as BRAINLIEST.
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