Question

Two number differ by 23.twice the smaller number is17lessthan the greater number.find the numbers

Answer 1

hi

let the number be x and y

Two number differ by 23

x - y = 23

x = 23 +y

twice the smaller number is17lessthan the greater number

so,

2y = x + 17

since x is 23 + y

2y = 23 + y +17

2y -y = 23+17

y = 40

x = 23 +y

= 40 + 23

= 63

so the numbers are 40 and 63

hope it helps u

:)

Answer 2

solution :-

let , the numbers are x , y

acourding to quetion:-

$1st \: case \: \\ x - y = 23............(1) \\2nd \: case \: \\ x + 17 = 2y \\ x - 2y = - 17............(2) \\ substrction \: eq(2)in(1) \\ y = 40 \\ put \: y \: value \: in \: eq(1) \\ x - 40 = 23 \\ x = 23 + 40 \\ x = 63 \\ y = 40 \\ i \: hope \: it \: is \: help$