Two number differ by 3 and their product is 504. Find the numbers.
Answers
SOLUTION :
Let the one number be x and other number be (x +3)
A.T.Q
x × (x + 3) = 504
x² + 3x = 504
x² + 3x - 504 = 0
x² + 24x - 21x - 504 = 0
[By middle term splitting]
x(x + 24) - 21 (x + 24) = 0
(x + 24) (x - 21) = 0
(x + 24) = 0 or (x - 21) = 0
x = - 24 or x = 21
Case 1 :
When x = - 24 , then other number be (x + 3) = (- 24 + 3) = - 21
Case 2 :
When x = 21 , then other number be (x + 3) = (21 + 3) = 24
Hence, the two numbers are (21, 24) and ( -21, -24) .
HOPE THIS ANSWER WILL HELP YOU….
Answer:
21 and -24
Step-by-step explanation:
Let one number = x
Second number = x - 3
Product = 504
x( x - 3 ) = 504
x² - 3x - 504 = 0
x² - 24x + 21x - 24 × 21 = 0
x( x - 24 ) + 21( x - 24 ) = 0
( x - 24 ) ( x + 21 ) = 0
Therefore ,
x - 24 = 0 or x + 21 = 0
x = 24 or x = - 21
1 ) if x = 24 second number is 21
2 ) if x = -21 , second number is -24