Two numbers are 20% and 25% less than the third number.How much % is the second number liss than the first?
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Answer:
Step-by-step explanation:
Lets assume three numbers are x, y and z.
Let's say z = 100
Then y is 25% less than z which is 100, so
y= 75
x is 20% less than 100, which will be
x= 80
Now we have values of x,y and z which are 80, 75 and 100 respectively.
% change= 80-75/80*100
% change=5/80 *100
= 6.25%
Therefore the second number is 6.25% lesser than the first one.
ivarun:
Let me know if you need clarification on any part.
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