Math, asked by NooraBaig4276, 1 year ago

Two numbers are 20% and 25% less than the third number.How much % is the second number liss than the first?

Answers

Answered by ivarun
0

Answer:

Step-by-step explanation:

Lets assume three numbers are x, y and z.

Let's say z = 100

Then y is 25% less than z which is 100, so

y= 75

x is 20% less than 100, which will be

x= 80

Now we have values of x,y and z which are 80, 75 and 100 respectively.

% change= 80-75/80*100

% change=5/80 *100

= 6.25%

Therefore the second number is 6.25% lesser than the first one.


ivarun: Let me know if you need clarification on any part.
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