Question

Two numbers are differ by 3 and their product is 504 find the numbers

Answer 1

The answer with solution in given in pic...
The numbers are 24 and 21...
OR
-21 and - 24...
As both the values satisfy the equations.

Answer 2

Let one number be x.

Then the other number differ by 3 = x - 3.   ------- (1)

Given that their product is 504.

x(x - 3) = 504

x^2 - 3x - 504 = 0

x^2 - 24x + 21x - 504 = 0

x(x - 24) + 21(x - 24) = 0

(x - 24)(x + 21) = 0

x = 24 (or) x= -21.

Therefore the numbers are 24 and - 21.

Substitute the value of x in (1), we get 24-3, -21-3

                                                              = 21,-24.


Therefore the numbers are 24,-21 (or) 21,-24.



Hope this helps!