Two numbers are given. If the first number is increased four times, their sum is increased three times. If the second is reduced four times, their sum is smaller for 8/5. Find the initial numbers
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Step-by-step explanation:
let the 2 numbers be x and y, and their sum is x+y
if the first number is increased four times, their sum is increased three times
4x+y = 3(x+y)
4x+y = 3x+3y
x= 2y
If the second is reduced four times, their sum is smaller for 8/5.
x+(y/4) =(8/5)
put x = 2y
2y + (y/4) =(8/5)
(9y/4)=(8/5)
9y=32/5
y= 32/45
x= 64/45
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