Two numbers are in ratio 4:5. If the difference of their cubes is 61 , find the numbers.
Answers
Answered by
3
let the numbers are 4x and 5x
(5x)^3 - (4x)^3 = 61
125x^3 - 64x^3 = 61
61x^3 = 61
x^3 = 1
x = 1
The numbers are
4x = 4×1 = 4
5x = 5×1 = 5
(5x)^3 - (4x)^3 = 61
125x^3 - 64x^3 = 61
61x^3 = 61
x^3 = 1
x = 1
The numbers are
4x = 4×1 = 4
5x = 5×1 = 5
Answered by
0
Given, a:b = 4:5
=> b = 5/4 a
Now,
a³ - (5a/4)³ = 61
=>64a³ - 125a³ = 61 * 64
=> -61a³ = 61 * 64
=> a³ = -64
=> a = -4
Therefore, the no.s are -4,-5.....
=> b = 5/4 a
Now,
a³ - (5a/4)³ = 61
=>64a³ - 125a³ = 61 * 64
=> -61a³ = 61 * 64
=> a³ = -64
=> a = -4
Therefore, the no.s are -4,-5.....
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