Two numbers are in ratio 4:5 the difference of the square is81 find the number
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2
Here's your answer
Let the common factor be x
1st number = 4x
2nd number= 5x
So,
(5x)² - (4x)² = 81
25x² - 16x² = 81
9x² = 81
x² = 9
x = 3
so,
1st number = 4x = 4 × 3 = 12
2nd number = 5x = 5 × 3 = 15
Hence ,
the two numbers are 12 and 15
Let the common factor be x
1st number = 4x
2nd number= 5x
So,
(5x)² - (4x)² = 81
25x² - 16x² = 81
9x² = 81
x² = 9
x = 3
so,
1st number = 4x = 4 × 3 = 12
2nd number = 5x = 5 × 3 = 15
Hence ,
the two numbers are 12 and 15
Anonymous:
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Answered by
0
x:y = 4:5
x = 4a
y = 5a
(5a)² - (4a)² = 81
25a² - 16a² = 81
9a² = 81
a² = 9
a = 3
=> x = 4 * 3 = 12
=> y = 5 *3 = 15
MARK AS THE BRAINLIEST
x = 4a
y = 5a
(5a)² - (4a)² = 81
25a² - 16a² = 81
9a² = 81
a² = 9
a = 3
=> x = 4 * 3 = 12
=> y = 5 *3 = 15
MARK AS THE BRAINLIEST
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