two numbers are in ratio 4:7. if thrice the larger be added to twice the smaller, the sum in 59 , find the numbers.
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Answered by
20
heya friend
here is your answer
the ratio of the two no. are 4:7
so, let the 2 no. be 4x and 7x
the larger no.is 7x and the smaller one 4x
here the given statement states that
thrice the larger no.= 3(7x)=21x
plus=sum= add= +
twice the smaller = 2(4x) =8x
is equal to = =
59
the equation is
21x + 8x = 59
they both are like terms so add them and keep variable as x
so, (21+8)x = 59
=> 29x = 59
=> x = 59/29
=> x = 2.3
=> x = 2.0 ( approx )
so, the no are
4x = 4*2= 8
7x = 7*2= 14
Hope it helps you
here is your answer
the ratio of the two no. are 4:7
so, let the 2 no. be 4x and 7x
the larger no.is 7x and the smaller one 4x
here the given statement states that
thrice the larger no.= 3(7x)=21x
plus=sum= add= +
twice the smaller = 2(4x) =8x
is equal to = =
59
the equation is
21x + 8x = 59
they both are like terms so add them and keep variable as x
so, (21+8)x = 59
=> 29x = 59
=> x = 59/29
=> x = 2.3
=> x = 2.0 ( approx )
so, the no are
4x = 4*2= 8
7x = 7*2= 14
Hope it helps you
Answered by
3
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