Math, asked by Saifullahkhanbaloch, 6 months ago

two numbers are in the ratio 3:4 if 6 is added to each term of the ratio there is an increase of 20% in the ratio find the first and second number.​

Answers

Answered by abhi569
17

Answer:

3 and 4

Step-by-step explanation:

As the ratio is 3:4, let the numbers are 3a and 4a.

When 6 is added to each term of the ratio there is an increase of 20%.

New numbers are 3a + 6 & 4a + 6.

New ratio is 3/4 + (20% of 3/4)= 3/4 + 3/20

= 18/20 = 9/10

=> (3a + 6) / (4a + 6) = 9/10

=> 10(3a + 6) = 9(4a + 6)

=> 30a + 60 = 36a + 54

=> 60 - 54 = 36a - 30a

=> 6 = 6a

=> 1 = a

Therefore, numbers are

3a = 3(1) = 3, and,

4a = 4(1) = 4

Answered by Anonymous
1005

Answer

Given :

  • two numbers are in the ratio 3:4 if 6 is added to each term of the ratio there is an increase of 20%

To Find :

  • the ratio find the first and second number.

Solution :

A / b = 3 / 4

a = 3b /4

a + 6 / b + 6 = 3/4 × 9/10

Substitute the value of à

3b /4 + 6/ b + 6 = 3 / 4 × 9/10

3b + 24/4b + 24 = 9/10

a = 3 , b = 4

Hence the Answer is 3 and 4

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