Question

Two numbers are in the ratio 3: 4. The difference between their squares is 28. Find the sum of the squares of these numbers?
1 point
120
14
400
100

Answer 1

Answer:

100 is the answer

Explanation: lets us take two number be x,y

then, x/y=3/4

x=3y/4 ---(1)

since the difference between their squares is 28,

y^2-x^2=28 ---(2)

substitute (1) in (2)

y^2-(3y/4)^2=28

y^2-(9y^2/16)=28

(16y^2-9y^2)/16=28

7y^2=28*16=448

y^2=448/7=64

y=8

substitute y in (2)

y^2-x^2=28

(8)^2-x^2=28

64-x^2=28

x^2=64-28

x^2=36

x=6

therefore sum of square of the two numbers 6^2+8^2=36+64=100.

Answer 2

Answer:

answer is 100

solution refer to attachment :)

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