two numbers are in the ratio 3 is to 4 and their sum of their cube is 307.125 .find the numbers
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Answer:
LET THE NO. BE 3X AND 4X
A/Q,
(3X)³+(4X)³=307.125
27X³+64X³=307.125
91X³=307.125
X³=3.375
X³=3375/1000
X³=15³/10³
X³=(15/10)³
X³=(1.5)³
X=1.5
HENCE THE NO. WILL BE 3X=3×1.5=4.5
4X=4×1.5=6
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