Two numbers are in the ratio 4:3 if they differ by 18 find these numbers
Answers
Answered by
11
Step-by-step explanation:
lets the number 4x and 3x
4x-3x =18
x =18
hence number are 4x18 and 3x18
72 and 54
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Answered by
10
GIVEN
Two numbers are in Ratio 4:3
And their Difference is 18
TO FIND :- Those Numbers
SOLUTION
- METHOD - 01(by linear equation in one variable)
If both the number are in ratio 4:3
Then Let one number be 4x
The Other will be 3x
Now , According to the Question
4x - 3x = 18
=> x = 18
So, both the numbers are
3x = 3 × 18 = 54
4x = 4 × 18 = 72
Hence the answers are 54 and 72
- METHOD - 02(By Linear equation in two variable)
Now,
Let x and y be the numbers
x:y = 4:3
=> x/y = 4/3
=> 3x = 4y ... eq.01
x - y = 18 ...eq.02
Now from eq.01 x = 4y/3
putting in eq. 02,
4y/3 - y = 18
=> (4y - 3y)/3 = 18
=> y/3 = 18
=> y = 54
Now putting this value in eq. 01
3x = 4 × 54
=> x = 216/3
=> x = 72
Hence, the numbers are 72 and 54.(ANS)
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