Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are:
(A) 40, 42
(B) 42, 48
(C) 40, 48
(D) 44, 50
Answers
Answered by
11
Answer: (C) 40,48
Explanation:
According to given information
x/y=5/6
=> 6x-5y=0 ........(I)
x-8/y-8=4/5
=> 5x-40=4y-32
=> 5x-4y=8 ...........(II)
from eq. (I)
6x-5y=0
=> x=5y/6
substituting in......(II)
5x-4y=8
=>5[5y/6]-4y=8
=>y/6=8
=>y=48
THEREFORE
x=5y/6
=>x=5×48/6
=> x=40
Answered by
0
Answer:
Two numbers are in the ratio 5 : 6
Let 5x, 6x be the two numbers
Then by the given condition
( 5x - 8) : ( 6x - 8) = 4 : 5
➙ ( 5x - 8) / ( 6x - 8) = 4 / 5
➙ 25x - 40 = 24x - 32
➙ 25x - 24x = 40 - 32
➙ x = 8
So the required numbers are (5×8) = 40 & (6×8) = 48
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