Question

Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are:

(A) 40, 42                                           

(B) 42, 48

(C) 40, 48                                           

(D) 44, 50


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Answer 1

Answer:

Option c=40 and 48

Step-by-step explanation:

SOLUTION:

let the two no be x and y

therefore x / y = 5 / 6

6 * x = 5 * y

6 * x - 5 * y = 0             * 5

    30 * x -     25 * y = 0 ..................(i)

also (x - 8)/(y - 8) = 4 / 5

5 * x - 40 = 4 * y - 32

5 * x - 4 * y - 8 = 0                 *6

30 * x - 24 * y - 48 = 0 .....................(ii)

subtracting  (i) from (ii)

y - 48 = 0

y = 48

putting y = 48 in x/y = 5/6

x/48 = 5/6

x = 5 * 48 / 6

x = 5 * 8

x = 40

therefore the two numbers are 40 and 48

HOPE IT HELPS

:)

Answer 2

ANSWER

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

HOPE it's helps you ❤️