Two numbers are in the ratio 5:6. If the sum of the numbers is 132,find the two numbers.
Answers
Answered by
22
let 1st no.=5x
2nd no.=6
a2q
5x+6x=132
11x=132
x=132/11
x=12
1st no.=5×12=60
2nd no.=6×12=72
2nd no.=6
a2q
5x+6x=132
11x=132
x=132/11
x=12
1st no.=5×12=60
2nd no.=6×12=72
Answered by
6
Heya Mate❤
It's really nice to meet uh
here's ua answer :
given ratio terms=5:6
we've to find such a number (say x)so that when (x)is multiplied with 5 and 6 gives the required numbers
NOW
let the first number=5x
and the 2 nd number=6x
5x+6x=132
11x=132
x=132/11 (transpostion)
x=12
now 5x=5×12=60
6x=6×12=72
CHECK FOR VERIFICATION
60+72=132
HOPE IT HELPS UH
BYE
SEE UH AGAIN!!!!
PlZ marK it as brainlist
It's really nice to meet uh
here's ua answer :
given ratio terms=5:6
we've to find such a number (say x)so that when (x)is multiplied with 5 and 6 gives the required numbers
NOW
let the first number=5x
and the 2 nd number=6x
5x+6x=132
11x=132
x=132/11 (transpostion)
x=12
now 5x=5×12=60
6x=6×12=72
CHECK FOR VERIFICATION
60+72=132
HOPE IT HELPS UH
BYE
SEE UH AGAIN!!!!
PlZ marK it as brainlist
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