Math, asked by manushri81, 11 months ago

Two numbers are in the ratio 5 : 7. If they differ by 8, then the smallest number is


Answers

Answered by Sauron
48

Answer:

The Numbers are 20 and 28.

Step-by-step explanation:

Given :

Ratio of the numbers = 5 : 7

Difference between the numbers = 8

To find :

The smaller number

Solution :

Let the numbers be :

  • One as 5x
  • Second as 7x

\sf{\Longrightarrow} \: 7x - 5x = 8 \\  \\ \sf{\Longrightarrow} \: 2x = 8 \\  \\ \sf{\Longrightarrow} \: x =  \dfrac{8}{2}  \\  \\ \sf{\Longrightarrow} \: x = 4

Value of 5x

\sf{\Longrightarrow} \: 5(4) \\  \\ \sf{\Longrightarrow} \: 20

Second Number = 20

\rule{300}{1.5}

Value of 7x

\sf{\Longrightarrow} \: 7(4) \\  \\ \sf{\Longrightarrow} \: 28

Second Number = 28

\therefore The Numbers are 20 and 28.

Answered by surajswarnkar6
28

Step-by-step explanation:

x=8+y

y=-28

then

x=8+(-28)

x=20

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