two numbers are in the ratio 7:5 if the sum of the numbers in840 find the number
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4
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Let the common ratio be
Then, the numbers be
=>
=>
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The numbers are
Hence, the numbers are and
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3
Let us take the given ratio be 7x: 5x.
Sum of the nos. = 7x+ 5x = 12x.
But it is given , So
ATQ, 12x =840
or x = 840/12 .
Therefore x = 70.
Therefore first no. =7x = 70×7=490.
second no. = 5x = 5× 70 = 350.
Sum of the nos. = 7x+ 5x = 12x.
But it is given , So
ATQ, 12x =840
or x = 840/12 .
Therefore x = 70.
Therefore first no. =7x = 70×7=490.
second no. = 5x = 5× 70 = 350.
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