Question

Two numbers are in the ratio 9: 2. If the smaller number is 320, find the larger number. ​

Answer 1

Answer:

first answer my question I will answer your question

Step-by-step explanation:

The distance between the points A(0.5) and B(-5,0) is

Answer 2

$\footnotesize \tt \blue{ Given:-}$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize \tt { Two \: numbers \: are \: in \: the \: ratio \: 9: 2.}$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize \tt \blue{ Solution:-}$

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$\footnotesize \tt {Let \: Smaller \: no. \: be \: 2x}$

$\footnotesize \tt {Let \: Larger \: no. \: be \: 9x}$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize \tt \blue{ According \: to \: question \: the \: equation \: becomes : }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize \tt{9x : 2x } = \tt{ \frac{320}{1} }$

$\tt{ \frac{9x}{2x} } = \tt{ \frac{1}{320} }$

$\: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize \tt \blue{Do \: cross \: multiplication}$

$\: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize\tt{ 9x \times 320 = 2x }$

$\footnotesize\tt{ 2880x = 2x }$

$\tt{ \frac{2880x}{2x} =} \footnotesize \tt{ \:Larger \: number }$

$\tt{ \cancel\frac{2880x}{2x} =} \footnotesize \tt{ \:Larger \: number }$

$\boxed{ \underline{ \underline{\footnotesize \tt{ 1440 = \:Larger \: number }}}} \: \blue \bigstar$