Math, asked by goundaditya17, 2 months ago

two numbers are in the ratio of 5:8 and their difference is 12. Find the numbers​

Answers

Answered by TheBrainliestUser
10

Answer:

  • The numbers are 32 and 20.

Step-by-step explanation:

Let us assume:

  • The two numbers are x and y where x > y.

Given that:

Two numbers are in the ratio of 5 : 8.

  • i.e., y : x = 5 : 8 ______(i)

Their difference is 12.

  • i.e., x - y = 12

⟶ x = 12 + y ______(ii)

To Find:

  • The numbers.

Finding the numbers:

  • In equation (i).

⟶ y : x = 5 : 8

  • Substituting the value of x from eqⁿ(ii).

⟶ y : (12 + y) = 5 : 8

⟶ y/(12 + y) = 5/8

  • Cross multiplication.

⟶ 8y = 5(12 + y)

⟶ 8y = 60 + 5y

⟶ 8y - 5y = 60

⟶ 3y = 60

⟶ y = 60/3

⟶ y = 20

  • Now in equation (ii).

⟶ x = 12 + y

⟶ x = 12 + 20

⟶ x = 32

The numbers are:

  • First number = 32
  • Second number = 20

Answered by abhishek917211
3

Finding the numbers:

In equation (i).

y:x = 5:8

Substituting the value of x from eq"(ii).

y : (12 + y) = 5:8

y/(12 + y) = 5/8

• Cross multiplication.

8y = 5(12 + y)

8y = 60 + 5y

8y - 5y = 60

3y = 60

y = 60/3

y = 20

• Now in equation (ii).

x = 12 + y

x = 12 + 20

x= 32

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