two numbers are in the ratio of 9:13 and their sum is 176. find the numbers.
Answers
Answered by
5
let the two numbers be 9x and 13x
then, 9x+13x+176
22x=176
x=176/22=8
so 9x=9*8=72
13x=13*8=104
hope it helps u in anyway and if it does then plz mark it as brainliest.
then, 9x+13x+176
22x=176
x=176/22=8
so 9x=9*8=72
13x=13*8=104
hope it helps u in anyway and if it does then plz mark it as brainliest.
Abhisheksingh563:
hiii
Answered by
1
Let the first required number be 9x
So, the second required number be 13x
A/Q,
Sum of required numbers=176
So, First required number =9x =9*8=72
And Second required number=13x=13*8=104
So, the second required number be 13x
A/Q,
Sum of required numbers=176
So, First required number =9x =9*8=72
And Second required number=13x=13*8=104
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