Question

two numbers are in the ratio3:5when 8 is added to each the ratio changes to 5:7. identify the two numbers​

Answer 1

Step-by-step explanation:

let me take ,

=>3x/5x

=>3x+8/5x+8 = 5/7 ( when added with 8)

=>7(3x+8)=5(5x+8)

=>21x+56=25x+40

=>4x = 16

x = 4....

so, 3x/5x => 3(4)/5(4) = 12/20

therefore the numbers are 12,20

Answer 2

• The two numbers are 12 and 30

Given:

The two numbers are in ratio 3:5

• Let one number be 3x and
• Another number be 5x

Now,

According to the question:

When 8 is added to both the numbers the ratio becomes to 5:7

To find:

The two numbers value

Now,

• The equation formed after observing the given data is,

$\implies \boxed{\frac{3x+\fred{8}}{5x+\red{8}}=\frac{\purple{5}}{\purple{7}}}$

[By cross multiplication, we get]

⇒ 5(5x + 8) = 7(3x + 8)

⇒ 25x + 40 = 21x + 56

⇒ 25x - 21x =  56 - 40

[By taking (21x) to LHS and (40) to RHS]

⇒ 4x = 16

⇒ x = 16 ÷ 4

[By transporting 4 to RHS]

⇒ x = 4

So,

• We got the value of x = 4

Now,

The two numbers are

• 3x = 3 * 4 = 12
• 5x = 5 * 4 = 20