two numbers are in the ratio4:5 if difference of tgeir cubes is 61 find tge numbers
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Let the smaller number be x
So the bigger number will be y
Now x/y = 4/5 (Given)
Cross multiplying, 5x= 4y
So, x= 4y/5
ATQ, the difference between their cubes is 61.
y³- x³ = 61 ...... (1)
Substitute x= 4y/5 in eq. (1)
y³ - (4y/5)³ = 61
y³ - 64y³/ 125 = 61
Multiply through by 125
125y³ - 64y³ = 7625
61 y³ = 7625
y³ = 7625/ 61
y³= 125
y= ∛125
y= 5
Now y= 5 so x= 4 (Because x= 4y/5)
So the bigger number will be y
Now x/y = 4/5 (Given)
Cross multiplying, 5x= 4y
So, x= 4y/5
ATQ, the difference between their cubes is 61.
y³- x³ = 61 ...... (1)
Substitute x= 4y/5 in eq. (1)
y³ - (4y/5)³ = 61
y³ - 64y³/ 125 = 61
Multiply through by 125
125y³ - 64y³ = 7625
61 y³ = 7625
y³ = 7625/ 61
y³= 125
y= ∛125
y= 5
Now y= 5 so x= 4 (Because x= 4y/5)
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