TWO NUMBERS ARE IN THR RATION OF 3:4 IF THEIR SUM IS 133 FIND THE NUMBERS
Answers
Answered by
22
let one number be 3x and other be 4x
3x+4x=133
7x =133
x=133/7
x=19
3x=19*3=57
4x=4*19=76
3x+4x=133
7x =133
x=133/7
x=19
3x=19*3=57
4x=4*19=76
AngeleenaJasmine:
easy way is:
easy way is 3+4=7X=133 X=133/7=19 now multiply this with 3 and four 3x19=57 and 4x19=76 therefore 57 and 76 are the numbers... is my answer helpful in detail
Answered by
10
Hey there !
Solution :
Let the two numbers be ' x ' and ' y '
It is given that x / y = 3 / 4
Hence x = 3y / 4 ------( Equation 1 )
It is given that x + y = 133
So we know x = 3y / 4. Hence substituting in the above equation we get,
3y / 4 + y = 133
Taking LCM we get,
3y + 4y / 4 = 133
7y / 4 = 133
=> 7y = 133 * 4
=> 7y = 532
=> y = 532 / 7 = 76
Hence the number ' y ' is 76.
We know ' x ' is 3y / 4. Hence we get,
x = 76 * 3 / 4
x = 57.
Hence the two numbers ' x ' and ' y ' are 57 and 76 respectively.
Hope my answer helped !
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