Question

Two numbers are less than third number by 50% and 60% Respectively by how much percentage is second number less than first number?

Answer 1

Answer:

Let the all three numbers be a, b and 100

• According to the Question :

⇒ a = (100 - 50)% of Third Number

⇒ a = 50% of 100

⇒ a = 50/100 × 100

⇒ a = 50

⇒ b = (100 - 60)% of Third Number

⇒ b = 40% of 100

⇒ b = 40/100 × 100

⇒ b = 40

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• Percent second no is less than first no :

⇢ Percent = (a - b)/a × 100

⇢ Percent = (50 - 40)/50 × 100

⇢ Percent = 10/50 × 100

⇢ Percent = 1/5 × 100

⇢ Percent = 20%

∴ Hence, Second number is 20% less than First number.

Answer 2

Question:

Two numbers are less than third number by 50% and 60% Respectively by how much percentage is second number less than first number?

Solution:

Assume the three numbers be a, b and 100

According to the Question :

➪a = (100 - 50)% of Third Number

➪a = 50% of 100

$a = \frac{50}{100} \times 100$

$a = 50$

➪ b = (100 - 60)% of Third Number

➪ b = 40% of 100

$b = \frac{40}{100} \times 100$

$b = 40$

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% second no is less than first no :

$\% = \frac{a - b}{a} \times 100$

$\% = \frac{50 - 40}{50} \times 100$

$\% = \frac{10}{50} \times 100$

$\% = \frac{1}{5} \times 100$

$\% = 20\%$

∴ the , Second number is 20% less than First number.

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