Question

two numbers are respectively 20%and 50% More than a 3rd no what % is the first of the second​

Answer 1

$\Large\underline{\underline{\sf \green{Given}:}}$

• Two numbers are respectively 20%and 50% More than a 3rd number

$\Large\underline{\underline{\sf \green{To\:Find}:}}$

• What % is the first of the second =?

$\Large\underline{\underline{\sf \green{Solution}:}}$

Let ,

third number = x

$\Large\underline{\underline{\sf \pink{According\:To\: Question}:}}$

First number

$\implies{\sf x+\dfrac{20}{100}×x}$

$\implies{\sf \dfrac{6x}{5} }$

Second number

$\implies{\sf x+\dfrac{50}{100} }$

$\implies{\sf \dfrac{3x}{2}}$

$\implies{\sf y\%\: of\:\dfrac{3x}{2}=\dfrac{6x}{5}}$

$\implies{\sf \dfrac{3x/2}{6x/2}×100 }$

$\implies{\sf y=80}$

$\Large\underline{\underline{\sf \green{Answer}:}}$

⛬ 80 % is the first of the second

Answer 2

▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬

$\huge\boxed{ANSWER}$

▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬

First Number

x+ 20×x/100

=6x/5

Second number

= x + 50/100

=3x/2

= y% of 3x/2 = 6x/5

= 3x×2/6x×2 × 100

y = 80

80 % is the first of the second