Question

Two numbers are respectively 20 percent& 50 percent more than a third number what percentage is the first of the second

Answer 1

let third number is x
then first number is (x+x20/100)=6x/5
second number is (x+x50/100)=3x/2
now according to question
percentage of first to second
={6x/5/(3x/2)} x 100=80%

Answer 2

let the third number be x
ist number =( 1+20/100)x=6x/5
second number=(1+50/100)x= 3x/2
percentage of the first to the second
=((6x/5)/(3x/2)x100)%
=80%