Question

Two numbers are respectively 23% and 46% more than third number .the first number is what percent of second number?

Answer 1

Let the third no be x. then , first no.=23x/100. and second no.=46x/100. then question is what % is first no of second no. =(23x/100)/(24x/100)*100. =(23x*100*100)/(46x/100). =50. =50%answer