two numbers are such that the ratio between them is 3 : 5 if each is increased by 10 , the ratio between the new number so formed is 5 : 7 find the original number
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Hey there!
Let the Multiplier be x
Then,
First number = 3x
Second number = 5x
i) Each is increased by 10:
3x + 10/5x + 10 = 5/7
(5x+10) = 7(3x+10)
25x + 50 = 21x + 70
25x - 21x = 70 - 50
4x = 20
x = 20/4
x = 5
So,
First number = 3x = 3(5) = 15
&
Second number = 5x = 5(5) = 25
Hence the original numbers are 15 and 25
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Let the Multiplier be x
Then,
First number = 3x
Second number = 5x
i) Each is increased by 10:
3x + 10/5x + 10 = 5/7
(5x+10) = 7(3x+10)
25x + 50 = 21x + 70
25x - 21x = 70 - 50
4x = 20
x = 20/4
x = 5
So,
First number = 3x = 3(5) = 15
&
Second number = 5x = 5(5) = 25
Hence the original numbers are 15 and 25
HOPE IT HELPED ^_^
#brainly star
#follow me
vicky136:
nice work bro
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