Question

two numbers are such that the ratio between them is 3:5.If each is increased by 10 ,the ratio between the new numbers so formed is 5:7 find the original numbers
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Answer 1

$\small\bold{\underline{\sf{\purple{Given:-}}}}$

• Two numbers are such that the ratio between them is 3:5.If each is increased by 10 ,the ratio between the new numbers so formed is 5:7

$\small\bold{\underline{\sf{\red{To\:Find:-}}}}$

• Original number

$\small\bold{\underline{\sf{\pink{Solution:-}}}}$

Let the number be 3x and 5x

According to the given condition

Each number is increased by 10 ,the ratio between the new numbers so formed is 5:7

3x + 10/5x + 10 = 5/7

7(3x + 10) = 5(5x + 10)

21x + 70 = 25x + 50

21x - 25x = 50 - 70

- 4x = - 20

x = 20/4 = 5

Hence,

Required numbers

First number = 3x = 15

Second number = 5x = 25

Answer 2

Answer:

First number = 15

Second number = 25

Step-by-step explanation:

Let,

First number = 3x

Second number = 5x

If each number is increased by 10

First number = 3x + 10

Second number = 5x + 10

Also,

The ratio between the new numbers so formed is 5:7

So,

⇒ $\frac{3x \: + \: 10}{5x \: + \: 10} \: = \: \frac{5}{7}$

⇒ 7 (3x + 10) = 5 ( 5x + 10)

⇒ 21x + 70 = 25x + 50

⇒ 21x - 25x = 50 - 70

⇒ - 4x = - 20

⇒ 4x = 20

⇒ x = 20 / 4

⇒ x = 5

________________________

★ Value of 3x :

⇒ 3 (5)

⇒ 15

_________________________

★ Value of 5x :

⇒ 5 (5)

⇒ 25

Therefore,

First number = 15

Second number = 25