Question

two numbers are x cube y square and x power4 y ? find the h.c.f and l.c.m​

Answer 1

Step-by-step explanation:

First no. = x³y²

Second no. = x⁴y

Hcf = x³y

Lcm = x³y² × x⁴y / x³y = x⁴y²

Answer 2

Answer:

First number = x^3y^2

second number = x^4y

soo the HCF for both the number is x^3y

and LCM is x^4y^2