Math, asked by pravinasolanki0301, 11 months ago


Two numbers differ by 2. Twice the smaller number is greater by 8 than the larger number.
Find the larger number.

Answers

Answered by Swarup1998
17

The larger number is 12.

Step-by-step explanation:

Let the two numbers be x and y with x > y.

By the given conditions,

• difference of the numbers is 2

i.e., x - y = 2 ..... (1)

• twice the smaller number is greater by 8 than the larger number

i.e., 2y = x + 8 ..... (2)

Using (2), from (1), we get

2x - 2y = 4

or, 2x - (x + 8) = 4

or, 2x - x - 8 = 4

or, x = 12

From (2), we get

2y = 12 + 8 = 20

or, y = 10

Therefore the larger number is 12.

Answered by sachingraveiens
3

Answer:

12

Step-by-step explanation:

Let the first no be" x "

the other no will be x +2

According to the question ,

2 x - ( x + 2 )  = 8

x - 2 = 8

x = 10

So the larger no will be 10 + 2 = 12

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