Question

Two numbers differ by 3 and their product is 504. Find the numbers.

Answer 1

Step-by-step explanation:

x-y = 3

xy = 504

(y+3)y = 504

y^2 + 3y - 504 = 0

Alpha = -3(+/-)√9+2016

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2

= -3(+/-)45

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2

So, y = 42/2 = 21

x = 21+3 = 24

Answer 2

Answer:

the numbers are X and (X+3)

now according to the problem

x×(X+3)=504

x^2 +3x-504=0

x^2 +24x-21x-504=0

(X+24)(x-21)=0

therefore...either X=-24...or X=21

when X=-24 ....the numbers are -24. and -21

when ...X=21. ...the numbers are 21...24