Question

Two numbers differ by 3 and their product is 504 . find the number

Answer 1

Let two numbers be x and y

x - y = 3 ------(1)

and xy = 504 ------(2)

then from first x = y + 3 -------(3)

Putting value of eq(3) in eq (2)

(y + 3) y = 504

y2 + 3y - 504 = 0

y2 + ( 24 - 21 ) y -504 = 0

y2 + 24y -21y -504 = 0

y ( y + 24 ) - 21 ( y + 24 ) = 0

( y - 21 ) ( y + 24 )

y = 21 or y = -24

then putting this value of y in eq(1)

we get x = 24 or x = - 21

Answer 2

Hey
I know it's a little messed up. Sorry for that.
Hope it helps :)