Question

Two numbers differ by 3. The sum of twice the smaller number and thrice
the greater number is 19. Find the numbers.​

Answer 1

Answer:

let the smaller number be x and y be the largest one.

Step-by-step explanation:

Given that the two number differ by 3 so.

y - x = 3

......(I)

also sum of twice the smaller number and thrice. the greater number will be. 19

so,

2x + 3y = 19

(II)

The equations obtained are

y - x = 3

2x + 3y = 19

multiplying (I) equation by 2 we get

2y - 2x = 6

....(III)

adding (III) and (II) we have

5y = 25

➡️ y = 25/5 = 5

Putting the value of y = 5 in (I) we get

5 - x = 3

➡️ -x = 3 - 5

➡️ -x = -2

➡️ x = 2

Thus, the two numbers are 2 and 5.

study well ....