Question

Two numbers differ by 4 and their product is 96.find the number

Answer 1

Answer:

x-y=4

xy=96

(x-y)^2=4^2

x^2+y^2-2xy=16

x^2+y^2=16+2×96=16+192=208

x+y ^2 =x^2+y^2+2xy

=208+192

=400

x+y=20

so x=12 y=8

Answer 2

Answer:

(12,8)(-12,-8)

Step-by-step explanation:

let the numbers be x and y

given x-y=4 and xy =96

so (y+4)y=96

y^2 +4y-96=0

y^2+12y-8y-96=0

y(y+12)-8(y+12)=0

(y+12)(y-8)=0

so y=8,-12

and x=12,-8