Two numbers have a sum of 15 and a product of 36. what are they
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hey, here is your answer.....
let the numbers be 'a' and 'b' ....
given, a+b = 15... and ab = 36.....
(a+b)^2 - 4ab = (a-b)^2....
(15)^2 - 4(36) = (a-b)^2.....
225-144 = (a-b)^2....
(a-b)^2 = 81....
(a-b) = 9....
let [(a+b) = 15] be eqn. 1 and [(a-b) = 9] be eqn. 2....
adding eqns. 1&2..... we get...
2a = 26...
a = 13....
and we got in eqn. 2 as (a-b) = 9....
then, b = a-9 .....
then, b = 13-9....
b = 4.....
therefore, a = 13, b = 4.......
hope this helps you.....
thank you....
plzz mark me as brainliest.....
let the numbers be 'a' and 'b' ....
given, a+b = 15... and ab = 36.....
(a+b)^2 - 4ab = (a-b)^2....
(15)^2 - 4(36) = (a-b)^2.....
225-144 = (a-b)^2....
(a-b)^2 = 81....
(a-b) = 9....
let [(a+b) = 15] be eqn. 1 and [(a-b) = 9] be eqn. 2....
adding eqns. 1&2..... we get...
2a = 26...
a = 13....
and we got in eqn. 2 as (a-b) = 9....
then, b = a-9 .....
then, b = 13-9....
b = 4.....
therefore, a = 13, b = 4.......
hope this helps you.....
thank you....
plzz mark me as brainliest.....
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