Math, asked by noahcole, 4 months ago

Two numbers total 73 and have a difference of 15

hamzahahmad190788: Let the first number = x

hamzahahmad190788: Numbers = x , x+15

hamzahahmad190788: => x + x+15 = 73 = 2x + 15

hamzahahmad190788: => 2x = 73 - 15 = 58

hamzahahmad190788: => x = 58/2 = 29

hamzahahmad190788: numbers = 29 , 44

hamzahahmad190788: i wrote the solution here just bcoz i love answering the questions. i dont need points neither freinds

Answers

Answered by Anonymous

The sum of two numbers is 15 and their difference is 73. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 15. In other words, x plus y equals 15 and can be written as equation A:

x + y = 15

The difference between x and y is 73. In other words, x minus y equals 73 and can be written as equation B:

x - y = 73

Now solve equation B for x to get the revised equation B:

x - y = 73

x = 73 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 15

73 + y + y = 15

73 + 2y = 15

2y = -58

y = -29

Now we know y is -29. Which means that we can substitute y for -29 in equation A and solve for x:

x + y = 15

x + -29 = 15

X = 44

Summary: The sum of two numbers is 15 and their difference is 73. What are the two numbers? Answer: 44 and -29 as proven here:

Sum: 44 + -29 = 15

Difference: 44 - -29 = 73

Answered by hamzahahmad190788

Answer:

29 , 44

Step-by-step explanation:

=> x + x+15 = 73 = 2x + 15

=> 2x = 73 - 15 = 58

=> x = 58/2 = 29

numbers = 29 , 44

Previous Question

Next Question