Question

Two numbers ,x and y , are such that the sum of their squares is equal to the sum of 64 and twice their product.
(i)Form an equation involving x and y
(ii)Hence,find the difference between the two numbers.

Answer 1

Step-by-step explanation:

By your question...what I understood is that

$x^{2} + y^{2} = 64 + 2xy \\ \\ 64 = x^{2} + y {}^{2} - 2xy \\ 64 = (x - y)^{2} \\ 8 = x - y \\ so \: the \: equation \: might \: be \: the \: x \: minus \: y \: whole \: thing \: and \: the \: difference \: is \: 8$